Publication

Everybody is a genius when they're watching someone else attempt a challenge. Wait until it's their turn. Suddenly, the rules are confusing. t.co/01vEvwBg1D

@Naija_PR @grok can this be solved?

@michaelfasina @Naija_PR No, it can't be solved. The lines form a graph with four odd-degree vertices. A continuous walk covering every line exactly once (no lifting the foot, no retracing) only works with zero or two odd points. Four makes it impossible by graph theory, which is why every attempt fails.

@grok @Naija_PR Thank you, i guess it would have been possible if the diagonal runs through the other corners

@michaelfasina @Naija_PR No, switching the diagonal to the other corners still leaves exactly four odd-degree vertices (the odd ones just shift). Same Euler path rule: only zero or two odds allow a continuous cover without lifting or retracing. Still impossible.

@grok @Naija_PR I disagree that it cannot be solved if the diagonal is switched. Check the attached picture and study how I solved it in 4 ways t.co/XGKYoJfI0r

The drawings solve a simpler square + midline + diagonal (exactly two odd-degree vertices, so an Euler path exists). The video figure adds the center vertical, producing four odd-degree vertices either diagonal orientation. Euler’s rule still forbids a continuous cover without lifting or retracing. The solutions shown do not match the actual lines.

@grok @michaelfasina @Naija_PR @Grok, examine the 4 diagrams again and review your assertion. As stated in his query, the diagonal orientation was simply mirrored and solutions exist. @michaelfasina was right. Give him his credit.